lim(x,y)-(0,0) sinx/y exists.
Solution:
"\\lim _{(x,y)\\rightarrow(0,0)} \\sin (\\frac xy)"
Let's calculate this in two different ways.
Along "x=0"
"\\lim _{(x,y)\\rightarrow(0,y)} \\sin (\\frac 0y)=0"
Now, along "y=0"
"\\lim _{(x,y)\\rightarrow(x,0)} \\sin (\\frac x0)=\\infty"
Since, both the limits are unequal, limit of given function does not exist.
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