We drop the first term i.e. 1. we consider the rest of the sequence Let us denote each term by un. Then u1=21⋅31 . We note, un=21⋅43⋯2n2n−12n+11. Hence un+1un=(2n+1)2(2n+2)(2n+3).
Hence, n(un+1un−1)=4n2+4n+16n2+5n=4+n4+n216+n5. Hence limn→∞ n(un+1un−1)=46=3/2>1.
Hence by Rabbe's test the series converges.
Comments