Question #161767

Prove that the series 1 + (1/2)·(1/3) + [(1·3)/(2· 4)]·(1/5) + [(1·3·5)/(2·4·6)]·(1/7) + ..... converges


1
Expert's answer
2021-02-24T06:39:53-0500

We drop the first term i.e. 1. we consider the rest of the sequence Let us denote each term by un.u_n. Then u1=1213u_1= \frac{1}{2}\cdot\frac{1}{3} . We note, un=12342n12n12n+1.u_n= \frac{1}{2}\cdot\frac{3}{4}\cdots \frac{2n-1}{2n}\frac{1}{2n+1}. Hence unun+1=(2n+2)(2n+3)(2n+1)2.\frac{u_{n}}{u_{n+1}}=\frac{(2n+2)(2n+3)}{(2n+1)^2}.

Hence, n(unun+11)=6n2+5n4n2+4n+1=6+5n4+4n+1n2.n(\frac{u_{n}}{u_{n+1}}-1)= \frac{6n^2+5n}{4n^2+4n+1}=\frac{6+\frac{5}{n}}{4+\frac{4}{n}+\frac{1}{n^2}}. Hence limn n(unun+11)=64=3/2>1.lim_{n\rightarrow \infty} \ n(\frac{u_n}{u_{n+1}}-1)=\frac{6}{4}=3/2>1.

Hence by Rabbe's test the series converges.


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