Answer to Question #160536 in Calculus for Jai

Question #160536

1. The electromotive force for an electric circuit with a simplified generator

is given by 𝑓(𝑑) = 40 sin 150 πœ‹π‘‘ where 𝑓(𝑑) Volts is present at 𝑑 seconds.

(a) Identify the amplitude, period, and frequency of the function.

(b) Find the maximum and minimum voltages


1
Expert's answer
2021-02-03T04:59:01-0500
  • The amplitude of a sin⁑x\sin x function is 11 and so as f(t)=40sin⁑(150Ο€t)f(t)=40\sin(150\pi t), the amplitude is 40 (the expression in the argument of a sin function does not affect it's amplitude). The period of a sin⁑x\sin x function is 2Ο€2 \pi, we will use it to find the period of f(t)f(t) : sin⁑(150Ο€t+2Ο€)=sin⁑(150Ο€t)\sin(150\pi t+2\pi)=\sin(150\pi t), now by factoring the expressions in the parentheses we find f(t+175)=f(t)f(t+\frac{1}{75})=f(t) and so the period is T=175T=\frac{1}{75}. The frequency is Ξ½=1T=75\nu = \frac{1}{T}=75.
  • The maximum and minimum of a sin⁑x\sin x function are βˆ’1,1-1, 1 and thus the minimum voltages are 40V,βˆ’40V40V, -40V (and they are attained at, for example, t+=1300,tβˆ’=1100t_+=\frac{1}{300}, t_-=\frac{1}{100}). The minimum voltage in the sense of an absolute value is 0V0V (and it is attained at, for example t0=0t_0=0).

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