Given g(n)-2n-5;f(n)=3n-4. Find (g°f)(-2n)
Solution:
(g∘f)(−2n)=g(f(−2n))=g(3⋅(−2n)−4)=g(−6n−4)=(g \circ f)(-2n)=g(f(-2n))=g(3\cdot(-2n)-4)=g(-6n-4)=(g∘f)(−2n)=g(f(−2n))=g(3⋅(−2n)−4)=g(−6n−4)=
−2(−6n−4)−5=12n+3-2(-6n-4)-5=12n+3−2(−6n−4)−5=12n+3
Answer: (g∘f)(−2n)=12n+3(g\circ f)(-2n)=12n+3(g∘f)(−2n)=12n+3 .
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