if z=x+y2x−y
Find dxdz and dydz
let u= 2x-y and v=x+y
using quotient ruledxdz=v2vdxdu−udxdv
dxdu=2
dzdv=1
dxdz=(x+y)2(x+y)(2)−(2x−y)1
dxdz=(x+y)22x+2y−2x+y
dxdz=(x+y)23y
using quotient ruledydz=v2vdydu−udydv
dxdu=−1
dzdv=1
dxdz=(x+y)2−1(x+y)−(2x−y)1
dxdz=(x+y)2−x−y−2x+y
dxdz=(x+y)2−3x
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