Question #160264

The  domain of the function f / g where f (x, y) = 2xy and

g(x, y) = x ²+ y² is R² .is it true or false. Give reasons for your answer


1
Expert's answer
2021-02-03T01:17:14-0500

First of all, as f,gf,g are polynomial, fg\frac{f}{g} are well defined on R2{g=0}\mathbb{R}^2 \setminus \{g=0\}. The only point where g(x,y)=0g(x,y)=0 is x=y=0x=y=0. Thus, the function is not defined on (0;0)(0;0). In addition, we can not extend f/gf/g to (0,0) in any natural way, as the limit limx,y0f(x,y)g(x.y)=limr02r2sinθcosθr2\lim_{x,y\to 0} \frac{f(x,y)}{g(x.y)} = \lim_{r\to 0} \frac{2 r^2 \sin \theta \cos \theta}{r^2} does not exist (as it depends on θ\theta). Therefore fg\frac{f}{g} is not defined on R2\mathbb{R}^2 and can't be extended in any natural way.


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