For a geometric sequence, t3 = 6 and ts = 2/81. Find t6
"t_8=ar^7=\\dfrac{2}{81}"
"\\dfrac{t_8}{t_3}=\\dfrac{ar^7}{ar^2}=r^5=\\dfrac{\\dfrac{2}{81}}{6}=\\dfrac{1}{3^5 }"
"r=\\dfrac{1}{3}"
"a(\\dfrac{1}{3})^2=6=>a=54"
"t_6=54(\\dfrac{1}{3})^5=\\dfrac{2}{9}"
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