Solution: Since {an} is a bounded sequence,there exists a M>0 such that∣an∣≤M for all n∈N.Since {bn} converges to zero, given ϵ>0,there exists n0 such that ∣bn∣<Mϵ for all n≥n0Now ∣anbn∣=∣an∣∣bn∣<MϵM=ϵ for all n≥n0Hence {an.bn} converges to 0.
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