Answer to Question #156322 in Calculus for Phyroe

Question

A particle travels along the parabola y=ax²+x+b. At what point do its abscissa and ordinate change at the same rate?

Answer 1

dy/dt = 2ax dx/dt + dx/dt

dy/dt = dx/dt(2ax + 1)

but dy/dt = dx/dt , so

1 = 2ax + 1

2ax = 0

x = 0

then y = b

at the point (0,b)