Question #145456
Determine the set of points at which the function is continuous.
1) F(x,y)=sin(xy)÷(e^x-y^2)
2) F(x,y)=x-y÷(1+x^2+y^2)
3) F(x,y)=arctan(x+√y)
4) F(x,y)=e^x^2y+√x+y^2
5) G(x,y)=ln(x^2+y^2-4)
1
Expert's answer
2020-11-25T16:20:24-0500

Given first function

(i) f(x,y)=sin(xy)exy2f(x,y)=\dfrac{sin(xy)}{e^x-y^2}


f(x,y)f(x,y) is continous for all values except at exy2=0e^x-y^2=0

    ex=y2\implies e^x=y^2


Taking log on both sides

    xloge=2logy    x=2logy\implies xlog e=2logy \\\implies x=2logy


(ii) f(x,y)=xy1+x2+y2f(x,y)=\dfrac{x-y}{1+x^2+y^2}

sincesince 1+x2+y2>01+x^2+y^2>0

f(x,y)f(x,y) is continous of alll value of xx and yy


(iii) f(x,y)=arctan(x+y)f(x,y)=arctan(x+\sqrt{y})

f(x,y)f(x,y) is continuous for all value of xx and yy except y<0y<0


(iv) f(x,y)=ex2y+x+y2f(x,y)=e^{x^2y}+\sqrt{x}+y^2


Given function is continuous for all values of xx and yy except at x<0x<0


(v) f(x,y)=ln(x2+y24)f(x,y)=ln(x^2+y^2-4)


Given function is continous for x2+y2>4x^2+y^2>4

    x0,y2\implies x\ge 0, y\ge 2

So the set of values for which given function are cintinuous

are x0,y0x\ge 0,y\ge 0





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