SolutionThe function f:IR2→IR defined by f(x)=c⋅x for a fixed c.
I'll show that f is continuous at a point x0∈IRn . Given any e>0, we need to show that there exists δ>0 such that ∥x−x0∥<δ⟹∣f(x)−f(x0)∣<e
Now consider ∣f(x)−f(x0)∣=∣c⋅x−c⋅x0∣=∣c⋅(x−x0)∣≤∥c∥ ∥x−x0∥
Choose δ=e∥c∥⟹∣f(x)−f(x0)∣≤∥c∥∥x−x0∥<∥c∥δ=e
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