Let "P" and "Q" be any two partitions of an interval "I""\\subseteq" "\\mathbb{R}" such that "P" is finer than "Q" . Then, by the definition of common refinement, we have that "P"#"Q=\\{K\\cap J: K\\in P, J\\in Q\\}"
Since "P" is finer than "Q" then for any "J\\in Q" "\\exists" "K\\in P" such that "J\\subseteq K". So, with this, it follows that "P"#"Q" is not empty. Hence, any two partitions have a common refinement.
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