Question #140339
For the following regions R and surface densities σ, find the total mass.
(a)R: 0≤y≤sin(pi x/L); 0≤x≤L; σ(x,y) =y.
(b) The region between the semicircles y=sqrt(1-x^2) and y=sqrt(4-x^2) and the segments of the x-axis joining them. The surface density is equal to the distance from any point to the origin.
1
Expert's answer
2020-11-09T19:01:48-0500

(a)

m=0Ldx0sinπxLydy=0Ly220sinπxLdx=120Lsin2πxLdx=m=\int_{0}^{L}dx\int_{0}^{sin\frac{\pi x}{L}}ydy=\int_{0}^{L}\frac{y^2}{2}\vert_{0}^{sin\frac{\pi x}{L}} dx=\frac{1}{2} \int_{0}^{L} sin^{2} \frac{\pi x}{L} dx=

=0L(1cos2πxL)dx=(xL2πsin2πxL)0L=L.= \int_{0}^{L}(1-cos\frac{2 \pi x}{L}) dx= (x-\frac{L}{2\pi}sin\frac{2 \pi x}{L})|_{0}^{L} =L.

(b)

σ=r,0φπ,1r2.\sigma=r, 0\leq \varphi\leq \pi, 1\leq r\leq 2.

m=0πdφ12rrdr=π12r2dr=13πr312=7π3.m=\int_{0}^{\pi}d\varphi \int_{1}^{2}r\cdot rdr=\pi \int_{1}^{2}r^2dr=\frac13\pi r^3|_{1}^{2}=\frac{7\pi}{3}.


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