Answer in Calculus for qwerty #136205

Question #136205

\int \left(\frac{sin\left(x+a\right)}{m}+\frac{cos\left(x+b\right)}{n}\right)dx

Expert's answer

\int \left(\frac{sin\left(x+a\right)}{m}+\frac{cos\left(x+b\right)}{n}\right)dx $\int \left(\frac{sin\left(x+a\right)}{m}+\frac{cos\left(x+b\right)}{n}\right)dx=\int \left(\frac{sin\left(x+a\right)}{m}\right)dx+\int \left(\frac{cos\left(x+b\right)}{n}\right)dx=$

$-\frac{cos\left(x+a\right)}{m}+\frac{sin\left(x+b\right)}{n}+C$

Answer: $\frac{sin\left(x+b\right)}{n}-\frac{cos\left(x+a\right)}{m}+C$

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