Answer to Question #136205 in Calculus for qwerty

Question

\int \left(\frac{sin\left(x+a\right)}{m}+\frac{cos\left(x+b\right)}{n}\right)dx

Answer 1

\int \left(\frac{sin\left(x+a\right)}{m}+\frac{cos\left(x+b\right)}{n}\right)dx$\int \left(\frac{sin\left(x+a\right)}{m}+\frac{cos\left(x+b\right)}{n}\right)dx=\int \left(\frac{sin\left(x+a\right)}{m}\right)dx+\int \left(\frac{cos\left(x+b\right)}{n}\right)dx=$

$-\frac{cos\left(x+a\right)}{m}+\frac{sin\left(x+b\right)}{n}+C$

Answer: $\frac{sin\left(x+b\right)}{n}-\frac{cos\left(x+a\right)}{m}+C$