A) Let f(x)=4−x^2 if x≤6 and x−1 if x>6
Find each of the following limits. If the limit does not exist, enter DNE below.
limx→6−f(x)=
limx→6+f(x)=
limx→6f(x)=
1
Expert's answer
2020-09-29T10:46:47-0400
limx->6_f(x) = limx->6_[4-x2]
= limh->0[4 - (6-h)2] (here, h is very small positive number tending to zero)
= - 32
limx->6+f(x) = limx->6+[x - 1]
= limh->0[(6 + h) - 1] (here, h is very small positive number tending to zero)
= 5
limx->6f(x) = DNE because limx->6_f(x) is not equal to limx->6+f(x) .
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