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Answer to Question #132345 in Calculus for Timmy
Question #132345
Differentiate f(x) = (5x³+7x )/(2x²-4x+5 ) using quotient rule.
Expert's answer
"f'(x)=\\left(\\frac{5x^3+7x}{2x^2-4x+5}\\right)'=\\\\\n{}=\\frac{(5x^3+7x)'(2x^2-4x+5)-(5x^3+7x)(2x^2-4x+5)'}{(2x^2-4x+5)^2}=\\\\\n{}=\\frac{(15x^2+7)(2x^2-4x+5)-(5x^3+7x)(4x-4)}{(2x^2-4x+5)^2}=\\\\\n{}=\\frac{10x^4-40x^3+61x^2+35}{(2x^2-4x+5)^2}."
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