Given function is "3 + \\int_k^x f(t)dt = e^{5x}"
we can write it as "\\int_k^x f(t)dt = e^{5x} - 3"
Differentiating both sides, we get
"f(x) = 5e^{5x}"
Now, from the equation given in question,
"3 + \\int_k^x 5e^{5x}dt = e^{5x}"
We get
"3 + [e^{5x}] - e^{5k} = e^{5x} \\implies k = \\frac{1}{5}ln(3)"
Comments
Leave a comment