Question #120948

Let F(x,y,z)=⟨2xy,x^2+z,y⟩ be a conservative vector field. A potential function of F


is

Select one:

a. x^2y+yz+z



b. x^2yz



c. x^2y+yz−87


d. x^6yz



e. ⟨x^2y,yz,z⟩

Expert's answer

F(x,y,z)=2xy,x2+z,yF(x,y,z)=⟨2xy,x^2+z,y⟩

We know that FF is the gradient of potential function U(x,y,z).U(x,y,z). So

Ux=2xyU(x,y,z)=x2y+f1(y,z),Uy=x2+zU(x,y,z)=x2y+yz+f2(x,z),Uz=yU(x,y,z)=yz+f3(x,y).\dfrac{\partial U}{\partial x} = 2xy \Rightarrow U(x,y,z) = x^2y + f_1(y,z), \\ \dfrac{\partial U}{\partial y} =x^2+z \Rightarrow U(x,y,z) = x^2y+yz+f_2(x,z), \\ \dfrac{\partial U}{\partial z} = y \Rightarrow U(x,y,z) =yz+f_3(x,y).

So U(x,y,x)=x2y+yz+const.U(x,y,x) = x^2y+yz+\mathrm{const}. Therefore, we should choose answer c. U(x,y,x)=x2y+yz87.U(x,y,x) = x^2y+yz-87.


LATEST TUTORIALS
APPROVED BY CLIENTS