Question #120848
what is the limit of cosx-2sinx over cosx+2sinx as x approaches to π/2.
1
Expert's answer
2020-06-08T20:14:09-0400

limxπ2cosx2sinxcosx+2sinx=[020+2]=1\lim\limits_{x\to\frac{\pi}{2}}\frac{\cos x-2\sin x}{\cos x+2\sin x}=[\frac{0-2}{0+2}]=-1


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