limx→π2cosx−2sinxcosx+2sinx=[0−20+2]=−1\lim\limits_{x\to\frac{\pi}{2}}\frac{\cos x-2\sin x}{\cos x+2\sin x}=[\frac{0-2}{0+2}]=-1x→2πlimcosx+2sinxcosx−2sinx=[0+20−2]=−1
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