Question #120887
As an engineer,you have been asked to design a cooling tower in the shape of hyperboloid of one sheet. the horizontal cross sections of the cooling tower are circular with 10m. the cooling tower is 40m tall with maximum cross-sectional radius of 15m. construct a mathematical equation for this cooling tower.
1
Expert's answer
2020-06-08T21:16:34-0400

Since horizontal radius is 10m and maximum radius is 15m. Since maximum height of the hyperboloid is 10m.


Equation of hyperboloid is x2a2+y2b2z2c2=1\frac{x^{2}}{a^{2}} + \frac{y^{2}}{b^{2}} - \frac{z^{2}}{c^{2}} = 1


Since region in horizontal surface is circular. so a = b = 10

Maximum radius will be when z is maximum but z will be 5m as half distance is up side and other half is in down side.


so equation will be

x2102+y2102z2c2=1\frac{x^{2}}{10^{2}} + \frac{y^{2}}{10^{2}} - \frac{z^{2}}{c^{2}} = 1


putting condition that x = y = 15 when z = 5 then c2=507c^{2} = \frac{50}{7}


Hence required equation is

x2102+y2102z2507=1\frac{x^{2}}{10^{2}} + \frac{y^{2}}{10^{2}} - \frac{z^{2}}{\frac{50}{7}} = 1



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