Since horizontal radius is 10m and maximum radius is 15m. Since maximum height of the hyperboloid is 10m.
Equation of hyperboloid is "\\frac{x^{2}}{a^{2}} + \\frac{y^{2}}{b^{2}} - \\frac{z^{2}}{c^{2}} = 1"
Since region in horizontal surface is circular. so a = b = 10
Maximum radius will be when z is maximum but z will be 5m as half distance is up side and other half is in down side.
so equation will be
"\\frac{x^{2}}{10^{2}} + \\frac{y^{2}}{10^{2}} - \\frac{z^{2}}{c^{2}} = 1"
putting condition that x = y = 15 when z = 5 then "c^{2} = \\frac{50}{7}"
Hence required equation is
"\\frac{x^{2}}{10^{2}} + \\frac{y^{2}}{10^{2}} - \\frac{z^{2}}{\\frac{50}{7}} = 1"
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