As shown in the figure, the area is divided to partsA=∫−71(−x+1−0)dx+∫111(x−1−0)dx=∫−71(−x+1)dx+∫111(x−1)dx=(−x2/2+x)∣−71+(x2/2−x)∣111=−0.5+1+49/2+7+121/2−11−0.5+1=82\text{As shown in the figure},\\ \text{ the area is divided to parts}\\ A=\int\limits_{-7}^1(-x+1-0)dx+\int\limits_1^{11}(x-1-0)dx\\ =\int\limits_{-7}^1(-x+1)dx+\int\limits_1^{11}(x-1)dx\\ =(-x^2/2+x)|_{-7}^1+(x^2/2-x)|_1^{11}\\ =-0.5+1+49/2+7\\ +121/2-11-0.5+1\\ =82As shown in the figure, the area is divided to partsA=−7∫1(−x+1−0)dx+1∫11(x−1−0)dx=−7∫1(−x+1)dx+1∫11(x−1)dx=(−x2/2+x)∣−71+(x2/2−x)∣111=−0.5+1+49/2+7+121/2−11−0.5+1=82