Question #120610

Find the area bounded by the curve y = |x−1|, the x-axis and the lines x = −7 and x = 11

Expert's answer



As shown in the figure, the area is divided to partsA=71(x+10)dx+111(x10)dx=71(x+1)dx+111(x1)dx=(x2/2+x)71+(x2/2x)111=0.5+1+49/2+7+121/2110.5+1=82\text{As shown in the figure},\\ \text{ the area is divided to parts}\\ A=\int\limits_{-7}^1(-x+1-0)dx+\int\limits_1^{11}(x-1-0)dx\\ =\int\limits_{-7}^1(-x+1)dx+\int\limits_1^{11}(x-1)dx\\ =(-x^2/2+x)|_{-7}^1+(x^2/2-x)|_1^{11}\\ =-0.5+1+49/2+7\\ +121/2-11-0.5+1\\ =82

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