We have h(x,y)=yln(x)So, we get hx(x,y)=xyandhy(x,y)=ln(x).at (1,5), we gethx(1,5)=5 andhy(1,5)=ln(1)=0.As at(1,5) the equation ofthe tangent plane to h(x,y) isz=hx(1,5)(x−1)+hy(1,5)(y−5)So, we getz=5(x−1).This implies that the correct answer isf.
Comments
Leave a comment