If the position vector of one end of a chord through the focus of the parabola y2= 8x is 1/2i + 2j, find the position vector of the other end.
Let the position vector of the other end of a chord. Then .
The parameter of the parabola is
The quadratic term in the equation is the y so the axis of the parabola coincides with the OX axis. Furthermore, the parabola lies on the positive side of the OX axis, since the coefficient accompanying the non-quadratic term (in this case the x) is 8 which is positive, so the focus lies at
We have that:
The position vector of the other end is and
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