How many angles are found in between 0 and 2π that satisfy the equation ItanxI = 5 ?
∣tan(x)∣=5|\tan(x)|=5∣tan(x)∣=5
This equation is equivalent to two equations:
tan(x)=5 or tan(x)=−5.\tan(x)=5\;or\;\tan(x)=-5.tan(x)=5ortan(x)=−5.
Each of these equations has two solutions on the interval [0,2π).[0,2\pi).[0,2π).
Thus, the equation ∣tan(x)∣=5|\tan(x)|=5∣tan(x)∣=5 has four solutions on the interval [0,2π).[0,2\pi).[0,2π).
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