The maximum actuating force on a double short shoe external drum brake illustrated in figure 1 below is 3 kN. If the coefficient of friction for the shoe lining is 0.3. 1.1 Determine the torque capacity of the brake for clockwise rotation of the drum. (11) Hint 1: Note the distance between the shoe and the pivot is not ignorable. Hint 2: Consider both shoes in your analysis. 1.2 Draw the forces acting on each shoe.
Taking moments at a point say O
"F_a*300= R_N1 *200+(150-120)\\\\\n2000*300= \\frac{F_{t1}}{\\mu}*200+30 F_{t1}\\\\\nF_{t1}=1020.34 N"
Taking moments at a point say A
"F_a*300= F_{t2} (150-120)= R_{N_2}*200\\\\\n2000*300+30F_{t2}= \\frac{F_{t2}}{\\mu}*200\\\\\nF_{t2}=1136.286 N"
Braking torque
"(1020.34+1136.286)150=323494.016 N"
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