Question #247430

if the % increase in power required for a helicopter to hover at an altitude above sea level is 6% higher that required to hover at sea level with the same figure of merit, determine the altitude. assume that the density change is 8% per km.


1
Expert's answer
2021-10-07T03:14:48-0400

% power increase=6%

Let the power be x

New power =1.06x

Density=massvolumeDensity=\frac{mass}{volume}

Mass=density*volume

Wsea˙Wmoun˙=hρmounρsea\frac{\dot{W_{sea}}}{\dot{W_{moun}}}=h\sqrt{\frac{\rho_{moun}}{\rho_{sea}}}

h=Wsea˙Wmoun˙1ρmounρseah=\frac{\dot{W_{sea}}}{\dot{W_{moun}}}*\frac{1}{\sqrt{\frac{\rho_{moun}}{\rho_{sea}}}}

h=1.0611.08h=1.06*\frac{1}{\sqrt{1.08}}

h=1.0200mh=1.0200m


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Comments

Mom
07.10.21, 12:32

Thankss

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