a)
Using F=ma
1471500Sin2.86-50*150=150*1000*a
a=0.439m/s2
Now using v2=u2+2as
v2=0+2*0.439*50
v=6.625m/s
b)
E1=21mv2+mgh1
E2=mgh2
E3=21kx2
x is the compression of spring
E4= rolling resistance * x
E1=E2+E3+E4
21mv2+mgh1=mgh2+21kx2+50∗150∗x
21mv2=mg(h2−h1)+21kx2+50∗150∗x
21mv2=mg∗Sinθ+21kx2+50∗150∗x
21∗150000∗(6.625)2=150000∗9.81∗Sin2.86+0.5
3292796.875=73421.50x+21∗25000000x2+7500x
391796.875=73421.5x+12500000x2+7500x
12500000xx2+80921.5x−3291796.875=0
x=0.50m
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