Calculate the internal energy of 0.3 m3 of steam at 4 bar and 0.95 dryness. If this steam is superheated at constant pressure through 30°C, determine the heat added and change in internal energy
"u = 0.3\\textsf{ m\u00b3}\\\\\np = 4\\textsf{ bar}\\\\\nx = 0.95\\\\\nT = 30 \\textsf{\u00b0C} = 30 +273 = 303\\textsf{ K}"
according to the pressure steam table corresponding to 4 bar
hf = 604.65 kJ/kg, uf = 604.22 kJ/kg, ug = 2553.1 kJ/kg.
Specific internal energy of wet steam,
"\\begin{aligned}\nu &= (1 \u2013 x)u_f+ xu_g\\\\\n\n&= (1 \u2013 0.95) \u00d7 604.22+ 0.95 \u00d7 2553.1\\\\\n&=2455.656\\textsf{ kJ\/kg} \\end{aligned}\\\\"
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