A ball is thrown vertically upward with a speed of 15 m/s. Determine the time of flight when it
returns to its original positio
u=15 m/sg=9.8 m/su = 15\textsf{ m/s} \\ g= 9.8\textsf{ m/s}u=15 m/sg=9.8 m/s
T=2ug=2×159.8=3.06sT = \dfrac{2u}{g} =\dfrac{2×15}{9.8}= 3.06sT=g2u=9.82×15=3.06s
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