propeller diameter=50 mm, diameter of pipe=150 mm, density of water=1000 kg/m3, and dynamic viscosity=0.00112 "\\frac{Ns}{m^2}" ,
Q (litres/s): 12 28 45 63 95 120 160 180
N (rps): 5 10 15 20 30 40 60 80
Now, for taking different flow rate we will find different velocity and then its related Reynold's number
"Q_x=\\frac{\\pi}{4}d^2V_x"
"V_x=0.0637 Q_X"
we will put different value of Q and then we get V
V (m/s) : .76 1.78 2.86 4.01 6.05 7.64 10.2 11.46
"Re=\\frac{\\rho\\times v\\times d}{\\mu}"
Re= 89285"\\times v"
Re (1) : 67857.14 158928.57 255357.14 358035.71 540178.57 910714.28 1023214.2
now similarly we will get data for other
Re(2) : 54321.22 178322.33 268934.22 389465.22 609234 1023657 1126493.3
Comments
Leave a comment