For equivalent processing time we know that,
"F=F_{ref}\\times 10^{\\frac{T_{ref}-T}{z}}"
here it is given that, "F_{ref}=F_{121}=40" min, so for temp
(a) T=100oC,
"F=F_{ref}\\times 10^{\\frac{T_{ref}-T}{z}}"
"F=40\\times 10^{\\frac{121-100}{10.5}}"
F= 4000 min
(b) For temp T= 150 oC
"F=F_{ref}\\times 10^{\\frac{T_{ref}-T}{z}}"
"F=40\\times 10^{\\frac{121-150}{10.5}}"
F= 0.0767 min
Comments
Leave a comment