The problem involves an adiabatic compression, therefore the governing equation will be
V1V2=41 P1=101kPa=0.101×106PaT1=20C=293.15KP2=1.5MPa=1.5×106Pa
P∗Vk=constant
and also, T∗Vk−1=constant
Considering two states, using the first equation:
0.101\times{10}^6\times4^k=1.5\times{10}^6\times1
=>4^k=14.81=>\ k\cong\ 1.944\
Now it’s possible to use the second equation
T1×V1k−1=T2×V2k−1293.15×40.944=T2⇒T2=1085.01 K =811.86 C