T1=T_1=T1= 400 K,T2=320KT_2= 320 KT2=320K and we know that,Cv=0.718C_v= 0.718Cv=0.718
Heat transfer= CvdT= 0718×(320−400)0718\times(320 -400)0718×(320−400)
Heat trasnfer= -57.44 kJ
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