Question #116903

Air initially at 75 psia and 65 0F is compressed to a final pressure of 300 psia and temperature of 320 0F. Find the polytropic exponent for the process

Expert's answer

Equation of polytropic process in terms of pressure and temperature is p1−nTn=constp^{1-n}T^{n} = const.

Writing this explicitly for initial and final state, obtain p11−nT1n=p21−nT2np_1^{1-n} T_1^{n} = p_2^{1-n}T_2^n, from where (p1p2)1−n=(T2T1)n\left( \frac{p_1}{p_2} \right) ^{1-n} = \left( \frac{T_2}{T_1} \right)^n, or p1p2=(p1T2p2T1)n\frac{p_1}{p_2} = \left( \frac{p_1 T_2}{p_2 T_1} \right)^n. Using last equation, n=log(p1T2p2T1)p1p2≈−6.7n = log_{\left( \frac{p_1 T_2}{p_2 T_1} \right)}\frac{p_1}{p_2} \approx -6.7.


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