"T_1 = 400^o F"
"T_2 = 1600^o F"
The key point for solving this problem is : the heat transfer for a non-flow reversible constant pressure process equals to the change in enthalpy of the system. Therefore,
"q = c_p(T_2-T_1)"
regardless of the temperature, cp could be found by
"c_p=R.k\/k-1"
"R= 0.06856 BTU\/lb ^oF" The value for k also assumed to be 1.4.
Thus, "c_p = 0.2399= 0.24"
"=> Q=0.24(1600-400)= 288 BTU\/lb"
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