T1=400oF
T2=1600oF
The key point for solving this problem is : the heat transfer for a non-flow reversible constant pressure process equals to the change in enthalpy of the system. Therefore,
q=cp(T2−T1)
regardless of the temperature, cp could be found by
cp=R.k/k−1
R=0.06856BTU/lboF The value for k also assumed to be 1.4.
Thus, cp=0.2399=0.24
=>Q=0.24(1600−400)=288BTU/lb
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