Question #115770
A closed tank contains 100 lbs of air at a pressure of 200 psia and a temperaure of 180 0F. The air is subsequently cooled to 80 0F. Find the: a.) the initial specific volume, ft3/lbm; b.) the volume of the tank, ft3; c.) the final specific volume, ft3/lbm; d.) the final pressure, psia.
1
Expert's answer
2020-05-15T09:47:22-0400

Pressure= 200 psia, Air present =100 lbs,T1=180oF,T2=80oF,T_1= 180 ^oF, T_2= 80^oF,

(a) Specific Volume,


P1V1=RT1P_1V_1=RT_1


200×V=53.33×(180+460)200\times V= 53.33\times (180+460)


V=170.656V=170.656 ft3ft^3/lbm

(b)

Volume of the tank ,


V= 170.656×10060=284.426ft3\frac {170.656 \times 100}{60}=284.426 ft^3

(c) for the final specific volume


P2V2=RT2P_2V_2=RT_2


V2=53..33×(80+460)200=143.991V_2= \frac{ 53..33\times (80+460)}{200}=143.991

(d)

Final pressure


P1V1T1=P2V2T2\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}


P2=333.33 psia



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