Schrodinger’s equation says that the dynamical evolution of Ψ is given by
i ∂t∂Ψ=− 2mℏ2∂x2∂2Ψ+V(x)Ψ
for a potential V(x)
Our statistical interpretation is provided by viewing Ψ(x,t)∗Ψ(x,t) as a density: ρ(x,t) =∣Ψ(x,t)∣2 so that
P(a,b)=∫abρ(x,t)dx=∫ab∣Ψ(x,t)∣2dx
dtd∫−∞∞∣Ψ(x,t)∣2dx=∫−∞∞∂t∂(Ψ∗(x,t)Ψ(x,t))dx
then we just need the temporal derivative of the norm (squared) of Ψ(x, t):
∂t∂(Ψ∗(x,t)Ψ(x,t))=∂t∂Ψ∗Ψ+Ψ∗∂t∂Ψ
Schrodinger’s equation, and its complex conjugate provide precisely the desired connection:
∂t∂Ψ=2miℏ∂x2∂2Ψ−ℏi V(x)Ψ
∂t∂Ψ∗=− 2miℏ∂x2∂2Ψ∗+ℏi V(x)Ψ∗
and we can write the above as:
∂t∂(Ψ∗(x,t)Ψ(x,t))= 2miℏ(−∂x2∂2Ψ∗Ψ+Ψ∗∂x2∂2Ψ).
Now, under the integral, we can use integration by parts1 to simplify the above – consider the first term :
∫−∞∞∂x2∂2Ψ∗Ψdx=∣∣(∂x∂Ψ∗Ψ)∣∣−∞∞−∫−∞∞∂x∂Ψ∗∂x∂Ψdx
We can get rid of the boundary term by assuming (an additional requirement) that Ψ(x,t)⟶0 as ∣x∣⟶∞
dtd∫−∞∞(Ψ∗(x,t)Ψ(x,t))= 2miℏ∫−∞∞[(−∂x2∂2Ψ∗Ψ+Ψ∗∂x2∂2Ψ)].
dtd∫−∞∞∣Ψ(x,t)∣2dx= 2miℏ∫−∞∞[∂x∂Ψ∗∂x∂Ψ−∂x∂Ψ∗∂x∂Ψ]dx
dtd∫−∞∞∣Ψ(x,t)∣2dx=0
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