Answer to Question #195380 in Quantum Mechanics for kruthik

Question #195380

A silver wire that is 2.5 mm in diameter and 37 cm long carries a current of 169 mA. How many electrons per second pass a given cross-section of the wire?

Expert's answer

By the definition of the current we have:

I=\dfrac{Q}{t},

Q=It.

From the other hand,

Q=ne.

Therefore, we can write:

It=ne,

\dfrac{n}{t}=\dfrac{I}{e},

\dfrac{n}{t}=\dfrac{169\cdot10^{-3}\ A}{1.6\cdot10^{-19}\ C}=1.06\cdot10^{18}\ \dfrac{electrons}{s}.

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