Optics Answers

A GeO2-doped silica-based optical fiber has the following parameters: (i) step-index
profile, (ii) refractive index difference at the core of 0.5%, and (iii) core diameter of
9.0 μm
(a) Calculate the refractive index of the fiber core and cladding at 1.310 and 1.55 μm
wavelengths
(b) What is the estimated loss of this fiber at the wavelengths mentioned?
(c) What are the V parameters of the fiber at these wavelengths?

You ordered a converging lens of focal length 3 m but the company delivered a lens whose focal length was only 1 m. You do not have time to wait for a replacement so you decide to correct the problem by placing a diverging lens next to the lens they sent you. What must the focal length be for this diverging lens?

A converging lens of focal length 24 cm is placed next to a converging lens of length 50 cm. What is the effective focal length for this combination?

A darkened room has a tiny aperture in the roof through which sunlight enters when the sun is directly overhead. What is the size of the sun's image on the floor 12 ft below the aperture? the sun is 93 million miles away, and its diameter is 865,000 miles.

A glass plate 0.9cm thick has a refractive index of 1.5 how long does it take for a ray of light to pass through the plate?

A 60 degree prism of refractive index is 1.5. what is the angle minimum deviation? calculate the angle of refraction of light passing through the prism at minimum deviation and the angle of incidence on the prism at minimum deviation

A coin of radius 'r' is kept at the bottom of a hemispherical vessel of radius 'a'. The coin is not visible when viewed from the edge of the vessel but just visible when a liquid of refractive index 'mu' is poured into the vessel. Prove that r=a( ((mu^2) - 1)/(mu^2 +1))

The critical angle for the material of a prism is 45° and its refracting angle is 30°.A monochromatic ray goes out perpendicular to the surface of emergence from the prism .Then the angle of incidence on the prism will be

Answer is 45°

The magnifications produced by a convex lens for two different positions of an object are m1 and m2 respectively (m1>m2) if "d" is the distance of seperation between the two positions of the object then focal length of the lens is
(1) √m1m2 (2) d/√m1-m2 (3) dm1m2/m1-m2 (4) d/m1-m2 correct answer is d/m1-m2 but how??

When we take an image from optical microscope suppose using 5x magnification of objective lens and eyepiece lens of 10x magnification, the image shows scale bar of micrometer. how does it gives value of 500 micrometer?
Like when i use 10x objective lens, scale bar shows value of 200 micrometer