Question #120038
When a sigle slit is replaced by the double slit arrangement, the intensity of central maximum is increased by?
1
Expert's answer
2020-06-08T10:30:17-0400

Since,

Idoubleslit=Iocos2(Δϕ2)I_{double \:slit}=I_o\cos^2(\frac{\Delta \phi}{2})

Where,

Δϕ=2πλdsin(θ)\Delta \phi=\frac{2\pi}{\lambda}d\sin(\theta)

Now, Central maximum occurs when dsin(θ)=λd\sin(\theta)=\lambda ,thus from above formula we get,

Idoubleslit=Iocos2(2π2)=Io(1)I_{double \:slit}=I_o\cos^2(\frac{2\pi}{2})=I_o\hspace{1cm}(1)

And

Isingleslit=Io(sin(β)β)2I_{single \: slit}=I_o\bigg(\frac{\sin(\beta)}{\beta}\bigg)^2

where,

β=πλasin(θ)\beta=\frac{\pi}{\lambda}a\sin(\theta)

Thus, we have central maximum when,θ0    β0\theta\rightarrow 0\implies \beta\rightarrow0 ,thussin(β)β1\frac{\sin(\beta)}{\beta}\rightarrow 1 ,

Hence,

Isingleslit=Io(2)I_{single \: slit}=I_o\hspace{1cm}(2)

Therefore, from equations (1) and (2) we get,

Intensity for both the slit at central maximum is equal.


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Comments

Assignment Expert
09.06.20, 20:45

Dear Dheeraj, please check first equation: (\Delta\phi/2)

Dheeraj
09.06.20, 06:43

in equation 1, you did 2π/2. But if we put dsinθ=λ, e will get only 2π. So ho did you got it?

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