Given, Position of 8th bright fringes is y=5mm=5×10−3m .
Wavelength is λ=6200A∘=62×10−8m ,Distance between slit and screen is D=0.8m ,
Let d is the distance between slits.
Clearly,
tan(θ)=Dy<<1⟹tan(θ)≈sin(θ)≈θ=Dy
Thus,formula for position of bright fringes is
dsin(θ)=nλ⟹d=ynλD Hence,
d=5×10−38×62×10−8×0.8⟹d=79.36×10−5m=793.6μm
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