Steam at 2 MPa and 250°C in a rigid cylinder is cooled until the quality is 30%. Find the heat rejected from the cylinder.
@ 2 Mpa and 250°C: υ = 0.11144 m3 /kg
u = 2679.6 kJ/kg
@ 2 Mpa, (saturated):υf = 0.0011767 m3 /kg
υg = 0.09963 m3 /kg
uf = 906.44kJ/kg
ug = 1693.8 kJ/kg
As the cylinder is rigid, therefore it's volume remains constant at initial and final states. The calculation part is given in the next step:
Internal energy at state 1:
Internal energy at state 2:
Heat rejected:
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