If 2.83 m3 of atmospheric air (101.3 kPa) at 0oC are compressed to a volume of 0.0283 m3 at a temperature of 76oC, what will be the pressure of the air in kPa.
p1V1T1=p2V2T2, ⟹ \frac{p_1V_1}{T_1}=\frac{p_2V_2}{T_2},\impliesT1p1V1=T2p2V2,⟹
p2=p1V1T2V2T1=12.95 MPa.p_2=p_1\frac{V_1T_2}{V_2T_1}=12.95~MPa.p2=p1V2T1V1T2=12.95 MPa.
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