Question #109194
Consider a one dimensional monatomic lattice with lattice constant 4.91A and atoms of mass 28amu. The speed of sound in the lattice is 11.6kms-1 . A) calculate the maximum frequency of waves that can be transmitted by the lattice.B) calculate the interatomic force constant of the lattice
1
Expert's answer
2020-04-13T10:21:23-0400

Molecular Physics | Thermodynamics

We need to calculate the maximum frequency of waves and calculate the inter atomic force

Solution:

Given

Mass of atoms = m=28 amu=28×1.67×1027kgm = 28 \space amu = 28 \times 1.67 \times 10^{-27} kg


speed of sound in the lattice =vs=11.6 km/s=11.6×103m/sv_s= 11.6 \space km /s = 11.6 \times 10^3 m/s


lattice constant = a=4.91Ao=4.91×1010m/sa = 4.91A^o = 4.91 \times 10^{-10} m/s


A).


 The maximum frequency of waves which was transmitted by the lattice is

wm=2a×vs=24.91×1010×11.6×103w_m =\frac {2}{a} \times v_s = \frac {2}{4.91 \times 10^{-10} } \times 11.6 \times 10^3

wm=4.725×1013rad/secw_m =4.725 \times 10^{13} rad/sec

B).

wm=4βmw_m = \sqrt {\frac {4\beta}{m}}

  Squaring on both sides

(wm)2=4βm(w_m)^2 = {\frac {4\beta}{m}}

β=m×β24=28×(4.725×1013)24\beta = \frac {m \times \beta^2 } {4} = \frac {28 \times (4.725 \times 10^{13})^2 } {4}

β=28×1.67×1027×22.325×10264\beta = \frac {28 \times 1.67 \times 10^{-27} \times 22.325 \times 10^{26}} {4}

β=1043.917×1014=26.0979N/m\beta = \frac {1043.917 \times 10^{-1}}{4} =26.0979 N/m


Answer: β=26.0979 N/m\beta = 26.0979 \space N/m


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