Question #109086
How many joules of heat must be absorbed to cool 5.00 kg of water from 75.0 degrees * C to 10.0^ C?
1
Expert's answer
2020-04-13T10:09:34-0400

The amount of heat that was absorbed to cool of water

Q=cmΔT=4200×5.00×65.0=1365000 J.Q=cm\Delta T=4200\times 5.00\times 65.0=1365000\:\rm J.

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