By the definition of the work done we have:
a) W=Fdcosθ=120N⋅5.0m⋅cos0∘=600J.W = Fdcos \theta = 120 N \cdot 5.0 m \cdot cos0^{\circ} = 600 J.W=Fdcosθ=120N⋅5.0m⋅cos0∘=600J.
b) W=Fdcosθ=120N⋅5.0m⋅cos30∘=520J.W = Fdcos \theta = 120 N \cdot 5.0 m \cdot cos30^{\circ} = 520 J.W=Fdcosθ=120N⋅5.0m⋅cos30∘=520J.
Answer:
a) W=600J.W = 600 J.W=600J.
b) W=520J.W = 520 J.W=520J.
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Assuming that the drag force exerted by a flowing fluid on a body is a function of the density, viscosity and velocity of the fluid and a characteristic length of a body developed a general equation.
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Dear visitor, please use panel for submitting new questions
Assuming that the drag force exerted by a flowing fluid on a body is a function of the density, viscosity and velocity of the fluid and a characteristic length of a body developed a general equation.
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