Solution:
Net force on Moon:
F=F12+F22=(2⋅1020)2+(4.3⋅1020)2=F=\sqrt{F^2_1+F^2_2}=\sqrt{(2\sdot{}10^{20})^2+(4.3\cdot{}10^{20})^2}=F=F12+F22=(2⋅1020)2+(4.3⋅1020)2=
=(2)2+(4.3)2⋅1020=22.49⋅1020==\sqrt{(2)^2+(4.3)^2}\cdot10^{20}=\sqrt{22.49}\cdot10^{20}==(2)2+(4.3)2⋅1020=22.49⋅1020=
=4.7⋅1020=4.7\cdot10^{20}=4.7⋅1020 N.
Answer:
Net force on Moon is 4.7⋅10204.7\cdot10^{20}4.7⋅1020 N.
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