Solution:
Net force on Moon:
"F=\\sqrt{F^2_1+F^2_2}=\\sqrt{(2\\sdot{}10^{20})^2+(4.3\\cdot{}10^{20})^2}="
"=\\sqrt{(2)^2+(4.3)^2}\\cdot10^{20}=\\sqrt{22.49}\\cdot10^{20}="
"=4.7\\cdot10^{20}" N.
Answer:
Net force on Moon is "4.7\\cdot10^{20}" N.
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