Question #151213
The curre Earth, called plate tectonics, tells us that the continents are in constant motion. Assume that the North American continent can be represented by a slab of rock 4700 km on a side and 28 km deep and that the rock has an average mass density of 2940 kg / (m ^ 3) The continent is moving at the rate of about 4.2 cm / y * e * a * r . What is the mass of continent ? Answer in units of kg
What is the kinetic energy of the continent
a jogger (75kg) has the same kinetic energy what would his speed be?
1
Expert's answer
2020-12-17T07:09:32-0500

a)     Mass=averagedensity()slabrock(a2)depth(h)Mass=()(a2)(h)Mass= average density(ℓ)* slab rock (a^2) * depth (h) Mass= (ℓ)(a^2) (h) Mass=averagedensity()slabrock(a2)depth(hMass= average density(ℓ)* slab rock (a^2) * depth (h)

Mass=()(a2)(h)Mass= (ℓ)(a^2) (h) Mass= (ℓ)(a^2) (h)

Mass of the continent= (2940) (4700000) ^2 (28000)

                                    =1.8181021KG1.818 * 10^21 KG



b)     Kineticenergy=½MV2=½(1.8181021)(4102)2=1.45441018JKinetic energy= ½ MV^2 =½ * (1.818 * 10^21) (4 * 10^-2) ^2 =1.4544 * 10^18 J Kineticenergy=½MV2Kinetic energy= ½ MV^2 Kineticenergy=½MV2Kinetic energy= ½ MV^2

                         =½(1.8181021)(4102)2½ * (1.818 * 10^21) (4 * 10^-2) ^2

= ½(1.8181021)(4102)2½ * (1.818 * 10^21) (4 * 10^-2) ^2

                           =1.45441018J1.4544 * 10^18 J  



c)     Speed of the jogger having the same kinetic energy as that of the continent

Hence K. E= 1.4544 * 10^18 J

Mass= 75kg75kg

FromtheK.E=½MV2From the K. E=½ MV^2

V=21.45441018J/75V= √2 * 1.4544 * 10^18 J/75

V=7.638108V=7.638 *10^8 m/sm/s


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