Let's denote E=1.3×10 J=13JE =1.3 \times10 \,J = 13 JE=1.3×10J=13J
m1m_1m1 - mass of the car, m2m_2m2 - mass of the truck. Also, m2m1=8.3\frac{m_2}{m_1} =8.3m1m2=8.3 and v1=v2v_1 = v_2v1=v2.
The kinetic energy of the body is
E=mv22\displaystyle E = \frac{mv^2}{2}E=2mv2
E2E1=m2v22m1v12=m2m1=8.3\displaystyle \frac{E_2}{E_1} = \frac{m_2v_2^2}{m_1v_1^2} = \frac{m_2}{m_1} =8.3E1E2=m1v12m2v22=m1m2=8.3
So, E2=8.3E1=8.3⋅13=107.9 JE_2 = 8.3 E_1 = 8.3 \cdot 13 = 107.9 \, JE2=8.3E1=8.3⋅13=107.9J
Answer: 107.9 J
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