Let's denote "E =1.3 \\times10 \\,J = 13 J"
"m_1" - mass of the car, "m_2" - mass of the truck. Also, "\\frac{m_2}{m_1} =8.3" and "v_1 = v_2".
The kinetic energy of the body is
"\\displaystyle E = \\frac{mv^2}{2}"
"\\displaystyle \\frac{E_2}{E_1} = \\frac{m_2v_2^2}{m_1v_1^2} = \\frac{m_2}{m_1} =8.3"
So, "E_2 = 8.3 E_1 = 8.3 \\cdot 13 = 107.9 \\, J"
Answer: 107.9 J
Comments
Leave a comment