Answer to Question #150946 in Mechanics | Relativity for jeric concepcion

Question

A liquid with specific gravity of 1.2 fills a volume. If the mass in the volume is 146kg
, what is the magnitude of the volume?

Answer 1

Solution:

$SG=1.2$

$m=146kg$

$p_{H_2O}=1000( \tfrac{kg}{m^3} )$

$The\; specific\; gravity\; is\; given \; by:$

$SG= \dfrac{p}{p_{H_2O}} = \dfrac{ \tfrac{m}{V} }{p_{H_2O}}$

$where\; p=\tfrac{m}{V}\; -is \;the\; density\; of\; the\; liquid,\; and\; p_{H_2O}-\;is \;the \;density\; of \;the \;water.$

$V= \dfrac{m}{SG*p_{H_2O}} = \dfrac{146}{1.2*1000( \tfrac{kg}{m^3} )}=0.121\;m^3$

$Answer:\: 0.121\;m^3$